Integer.parseInt() and StringTokenizer

  private int getSize(String sizeString , int defaultSize) {
	try {
	  return(Integer.parseInt(sizeString)); 
	} catch (NumberFormatException nfe) {
	  return(defaultSize);
	}
  }

  private String makeList(String str){
	String resultList = "
\n";
	StringTokenizer List = new StringTokenizer(str, ",");
	while(List.hasMoreTokens()){
		resultList += "
" + List.nextToken() + "\n";
	}
	resultList += "
\n";
	return(resultList);
  }
  

getSize chuyen so format String -> integer
nakeList dung StringTokenizer, tuong tu voi Enumeration

Fixing the Eclipse PermGen Space (Out of Memory) Error When Using JDK 1.6.0_21

eclipse.ini

-startup
plugins/org.eclipse.equinox.launcher_1.1.0.v20100507.jar
--launcher.library
plugins/org.eclipse.equinox.launcher.win32.win32.x86_1.1.0.v20100503
-product
org.eclipse.epp.package.jee.product
--launcher.defaultAction
openFile
--launcher.XXMaxPermSize
256m
-showsplash
org.eclipse.platform
--launcher.XXMaxPermSize
256m
--launcher.defaultAction
openFile
-vmargs
-Dosgi.requiredJavaVersion=1.5
-Xms40m
-Xmx512m
-XX:MaxPermSize=256m

http://www.coreservlets.com/Apache-Tomcat-Tutorial/eclipse-jdk1.6.0_21-permgen-bug.html

ERROR:
http://www.eclipse.org/forums/index.php?t=msg&goto=542715&

Line break

		String lineSeparator = (String) java.security.AccessController.doPrivileged(new sun.security.action.GetPropertyAction("line.separator"));
		System.out.print("Line break" + lineSeparator + "How?");

range value of byte

		byte[] b = new byte[400];
		int j = 0;
		for (int i = -128; i < 128; i++){
			b[j] = i;
			System.out.println(j + " " + i);
			j++;

		}

Gia tri se lap lai mac du da toi 127, lap lai tu -128, cu tiep tuc nhu the', that. la....

vi tu 127, tang them 1 don vi se thanh -128. va vi the ma khong thoat khoi vog lap